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$firstN (aggregation accumulator)
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Definition
Syntax
{ $firstN: { input: <expression>, n: <expression> } }
input
specifies the field(s) from the document to take the firstn
of. Input can be any expression.n
has to be a positive integral expression that is either a constant or depends on the_id
value for$group
. For details see group key example.
Behavior
Null and Missing Values
$firstN
does not filter out null values.$firstN
converts missing values to null.
Consider the following aggregation that returns the first five documents from a group:
db.aggregate( [ { $documents: [ { playerId: "PlayerA", gameId: "G1", score: 1 }, { playerId: "PlayerB", gameId: "G1", score: 2 }, { playerId: "PlayerC", gameId: "G1", score: 3 }, { playerId: "PlayerD", gameId: "G1"}, { playerId: "PlayerE", gameId: "G1", score: null } ] }, { $group: { _id: "$gameId", firstFiveScores: { $firstN: { input: "$score", n: 5 } } } } ] )
In this example:
$documents
creates the literal documents that contain player scores.$group
groups the documents bygameId
. This example has only onegameId
,G1
.PlayerD
has a missing score andPlayerE
has a nullscore
. These values are both considered as null.The
firstFiveScores
field is specified usinginput : "$score"
and returned as an array.Since there is no sort criteria the first 5
score
fields are returned.
[ { _id: 'G1', firstFiveScores: [ 1, 2, 3, null, null ] } ]
Comparison of $firstN
and $topN
Accumulators
Both $firstN
and $topN
accumulators can accomplish similar
results.
In general:
If the documents coming into
$group
are already ordered, you should use$firstN
.If you're sorting and selecting the top
n
elements then you can use$topN
to accomplish both tasks with one accumulator.$firstN
can be used as an aggregation expression,$topN
cannot.
Restrictions
Window Function and Aggregation Expression Support
$firstN
is supported as an
aggregation expression.
For details on aggregation expression usage see Using $firstN as an Aggregation Expression.
$firstN
is supported as a
window operator
.
Memory Limit Considerations
Aggregation pipelines which call $firstN
are subject to the
100 MB limit. If this
limit is exceeded for an individual group, the aggregation fails
with an error.
Examples
Consider a gamescores
collection with the following documents:
db.gamescores.insertMany([ { playerId: "PlayerA", gameId: "G1", score: 31 }, { playerId: "PlayerB", gameId: "G1", score: 33 }, { playerId: "PlayerC", gameId: "G1", score: 99 }, { playerId: "PlayerD", gameId: "G1", score: 1 }, { playerId: "PlayerA", gameId: "G2", score: 10 }, { playerId: "PlayerB", gameId: "G2", score: 14 }, { playerId: "PlayerC", gameId: "G2", score: 66 }, { playerId: "PlayerD", gameId: "G2", score: 80 } ])
Find the First Three Player Scores for a Single Game
You can use the $firstN
accumulator to find the first three scores
in a single game.
db.gamescores.aggregate( [ { $match : { gameId : "G1" } }, { $group: { _id: "$gameId", firstThreeScores: { $firstN: { input: ["$playerId", "$score"], n:3 } } } } ] )
The example pipeline:
Uses
$match
to filter the results on a singlegameId
. In this case,G1
.Uses
$group
to group the results bygameId
. In this case,G1
.Specifies the fields that are input for
$firstN
withinput : ["$playerId"," $score"]
.Uses
$firstN
to return the first three documents for theG1
game withn : 3
.
The operation returns the following results:
[ { _id: 'G1', firstThreeScores: [ [ 'PlayerA', 31 ], [ 'PlayerB', 33 ], [ 'PlayerC', 99 ] ] } ]
Finding the First Three Player Scores Across Multiple Games
You can use the $firstN
accumulator to find the first n
input fields in each game.
db.gamescores.aggregate( [ { $group: { _id: "$gameId", playerId: { $firstN: { input: [ "$playerId","$score" ], n: 3 } } } } ] )
The example pipeline:
Uses
$group
to group the results bygameId
.Uses
$firstN
to return the first three documents for each game withn: 3
.Specifies the fields that are input for
$firstN
withinput : ["$playerId", "$score"]
.
The operation returns the following results:
[ { _id: 'G1', playerId: [ [ 'PlayerA', 31 ], [ 'PlayerB', 33 ], [ 'PlayerC', 99 ] ] }, { _id: 'G2', playerId: [ [ 'PlayerA', 10 ], [ 'PlayerB', 14 ], [ 'PlayerC', 66 ] ] } ]
Using $sort
With $firstN
Using a $sort
stage earlier in the pipeline can influence the
results of the $firstN
accumulator.
In this example:
{$sort : { score : -1 } }
sorts the highest scores to the back of each group.firstN
returns the three highest scores from front of each group.
db.gamescores.aggregate( [ { $sort : { score : -1 } }, { $group: { _id: "$gameId", playerId: { $firstN: { input: [ "$playerId","$score" ], n: 3 } } } } ] )
The operation returns the following results:
[ { _id: 'G2', playerId: [ [ 'PlayerD', 80 ], [ 'PlayerC', 66 ], [ 'PlayerB', 14 ] ] }, { _id: 'G1', playerId: [ [ 'PlayerC', 99 ], [ 'PlayerB', 33 ], [ 'PlayerA', 31 ] ] } ]
Computing n
Based on the Group Key for $group
You can also assign the value of n
dynamically. In this example,
the $cond
expression is used on the gameId
field.
db.gamescores.aggregate([ { $group: { _id: {"gameId": "$gameId"}, gamescores: { $firstN: { input: "$score", n: { $cond: { if: {$eq: ["$gameId","G2"] }, then: 1, else: 3 } } } } } } ] )
The example pipeline:
Uses
$group
to group the results bygameId
.Specifies the fields that input for
$firstN
withinput : "$score"
.If the
gameId
isG2
thenn
is 1, otherwisen
is 3.
The operation returns the following results:
[ { _id: { gameId: 'G1' }, gamescores: [ 31, 33, 99 ] }, { _id: { gameId: 'G2' }, gamescores: [ 10 ] } ]
Using $firstN
as an Aggregation Expression
You can also use $firstN
as an aggregation expression.
In this example:
$documents
creates the literal document that contains an array of values.$project
is used to return the output of$firstN
._id
is omited from the output with_id : 0
.$firstN
uses the input array of[10, 20, 30, 40]
.The first three elements of the array are returned for the input document.
db.aggregate( [ { $documents: [ { array: [10, 20, 30, 40] } ] }, { $project: { firstThreeElements:{ $firstN: { input: "$array", n: 3 } } } } ] )
The operation returns the following results:
[ { firstThreeElements: [ 10, 20, 30 ] } ]