$set (aggregation)
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Definition
Note
Disambiguation
$set
New in version 4.2.
Adds new fields to documents.
$set
outputs documents that contain all existing fields from the input documents and newly added fields.The
$set
stage is an alias for$addFields
.Both stages are equivalent to a
$project
stage that explicitly specifies all existing fields in the input documents and adds the new fields.
Syntax
$set
has the following form:
{ $set: { <newField>: <expression>, ... } }
Specify the name of each field to add and set its value to an aggregation expression or an empty object. For more information on expressions, see Expressions.
Important
If the name of the new field is the same as an existing field name
(including _id
), $set
overwrites the existing value
of that field with the value of the specified expression.
Behavior
$set
appends new fields to existing documents. You can include one or more$set
stages in an aggregation operation.$set
accepts the embedding of objects where you can set a value to an aggregation expression or to an empty object. For example, the following nested objects are accepted:{$set: { a: { b: { } } } } To add a field or fields to embedded documents (including documents in arrays) use the dot notation. See example.
To add an element to an existing array field with
$set
, use with$concatArrays
. See example.
Examples
Using Two $set
Stages
Create a sample scores
collection with the following:
db.scores.insertMany([ { _id: 1, student: "Maya", homework: [ 10, 5, 10 ], quiz: [ 10, 8 ], extraCredit: 0 }, { _id: 2, student: "Ryan", homework: [ 5, 6, 5 ], quiz: [ 8, 8 ], extraCredit: 8 } ])
The following operation uses two $set
stages to
include three new fields in the output documents:
db.scores.aggregate( [ { $set: { totalHomework: { $sum: "$homework" }, totalQuiz: { $sum: "$quiz" } } }, { $set: { totalScore: { $add: [ "$totalHomework", "$totalQuiz", "$extraCredit" ] } } } ] )
The operation returns the following documents:
{ "_id" : 1, "student" : "Maya", "homework" : [ 10, 5, 10 ], "quiz" : [ 10, 8 ], "extraCredit" : 0, "totalHomework" : 25, "totalQuiz" : 18, "totalScore" : 43 } { "_id" : 2, "student" : "Ryan", "homework" : [ 5, 6, 5 ], "quiz" : [ 8, 8 ], "extraCredit" : 8, "totalHomework" : 16, "totalQuiz" : 16, "totalScore" : 40 }
Adding Fields to an Embedded Document
Use dot notation to add new fields to embedded documents.
Create a sample collection vehicles
with the following:
db.vehicles.insertMany([ { _id: 1, type: "car", specs: { doors: 4, wheels: 4 } }, { _id: 2, type: "motorcycle", specs: { doors: 0, wheels: 2 } }, { _id: 3, type: "jet ski" } ])
The following aggregation operation adds a new field fuel_type
to
the embedded document specs
.
db.vehicles.aggregate( [ { $set: { "specs.fuel_type": "unleaded" } } ] )
The operation returns the following results:
{ _id: 1, type: "car", specs: { doors: 4, wheels: 4, fuel_type: "unleaded" } } { _id: 2, type: "motorcycle", specs: { doors: 0, wheels: 2, fuel_type: "unleaded" } } { _id: 3, type: "jet ski", specs: { fuel_type: "unleaded" } }
Overwriting an existing field
Specifying an existing field name in a $set
operation
causes the original field to be replaced.
Create a sample collection called animals
with the following:
db.animals.insertOne( { _id: 1, dogs: 10, cats: 15 } )
The following $set
operation overrides the cats
field:
db.animals.aggregate( [ { $set: { "cats": 20 } } ] )
The operation returns the following document:
{ _id: 1, dogs: 10, cats: 20 }
It is possible to replace one field with another. In the following
example the item
field substitutes for the _id
field.
Create a sample collection called fruits
contains the following
documents:
db.fruits.insertMany([ { "_id" : 1, "item" : "tangerine", "type" : "citrus" }, { "_id" : 2, "item" : "lemon", "type" : "citrus" }, { "_id" : 3, "item" : "grapefruit", "type" : "citrus" } ])
The following aggregration operation uses $set
to replace the
_id
field of each document with the value of the item
field,
and replaces the item
field with a string "fruit"
.
db.fruits.aggregate( [ { $set: { _id : "$item", item: "fruit" } } ] )
The operation returns the following:
{ "_id" : "tangerine", "item" : "fruit", "type" : "citrus" } { "_id" : "lemon", "item" : "fruit", "type" : "citrus" } { "_id" : "grapefruit", "item" : "fruit", "type" : "citrus" }
Add Element to an Array
Create a sample scores
collection with the following:
db.scores.insertMany([ { _id: 1, student: "Maya", homework: [ 10, 5, 10 ], quiz: [ 10, 8 ], extraCredit: 0 }, { _id: 2, student: "Ryan", homework: [ 5, 6, 5 ], quiz: [ 8, 8 ], extraCredit: 8 } ])
You can use $set
with a $concatArrays
expression to add an element to an existing array field. For example,
the following operation uses $set
to replace the
homework
field with a new array whose elements are the current
homework
array concatenated with another array containing a new
score [ 7 ]
.
db.scores.aggregate([ { $match: { _id: 1 } }, { $set: { homework: { $concatArrays: [ "$homework", [ 7 ] ] } } } ])
The operation returns the following:
{ "_id" : 1, "student" : "Maya", "homework" : [ 10, 5, 10, 7 ], "quiz" : [ 10, 8 ], "extraCredit" : 0 }
Creating a New Field with Existing Fields
Create a sample scores
collection with the following:
db.scores.insertMany([ { _id: 1, student: "Maya", homework: [ 10, 5, 10 ], quiz: [ 10, 8 ], extraCredit: 0 }, { _id: 2, student: "Ryan", homework: [ 5, 6, 5 ], quiz: [ 8, 8 ], extraCredit: 8 } ])
The following aggregation operation adds a new field quizAverage
to each document that contains the average of the quiz
array.
db.scores.aggregate( [ { $set: { quizAverage: { $avg: "$quiz" } } } ] )
The operation returns the following documents:
[ { _id: 1, student: 'Maya', homework: [ 10, 5, 10 ], quiz: [ 10, 8 ], extraCredit: 0, quizAverage: 9 }, { _id: 2, student: 'Ryan', homework: [ 5, 6, 5 ], quiz: [ 8, 8 ], extraCredit: 8, quizAverage: 8 } ]